Asked by Alice

For diagonals of square Abcd intersect at e . If ae =2x+6 and bd =6x-10 find ac
Answered by Reiny
The diagonals of a square bisect each other into 4 equal lengths.
AE = 2x+6 is half of a diagonal, but
BD = 6x-10 is the entire diagonal, so its half would be 3x-5

then 3x-5 = 2x+6
x = 11
so AC = BD = 6x-10 = 6(11) - 10 = 56
Answered by Alice
Thank you so much!
Answered by lusia
The diagonals of square ABCD intersect at E. If AE = 2x + 6 and BD = 6x – 10, find AC.
Answered by sanaa
In 13-16, the diagonals of rectangle ABCD intersect at E in the diagram to the right.
13. Let and . Find AC, BD, AE, and BE.
Answered by Vickii
It's 56
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