Asked by Jen
Rectangle ABCD has diagonals AC and BD. E is the point of intersection of the two diagonals. If the area of triangle AEB is 8, what is the area of triangle ACD?
Answers
Answered by
drwls
ACD has half the area if the rectangle.
AEB is less than half of the rectangle, and its fraction of the whole depends upon the aspect ratio (AB/BC) of the triangle.
More information is needed to answer the question.
AEB is less than half of the rectangle, and its fraction of the whole depends upon the aspect ratio (AB/BC) of the triangle.
More information is needed to answer the question.
Answered by
Reiny
In a rectangle, the diagonals bisect each other giving you four triangles of equal area.
so triangle ACD = 16
so triangle ACD = 16
Answered by
drwls
Whoops! I forgot that equal-area theorem. Thanks again, Reiny.
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