Asked by Knights

Isosceles triangle ABC has sides of length AB=AC=25 and BC=40 . Find the area of a semicircle inscribed in triangle ABC with diameter along BC .

Please help I do not know how to start....

Answers

Answered by Steve
If the center of the semi-circle is O, draw OD where D is the point where AC is tangent to o the circle.

Since OD┴AD, if the radius is r, let a=AD and b=DC, so a+b=25

r^2 + a^2 =15^2
r^2 + b^2 = 20^2

equating r^2, we get
15^2-a^2 = 20^2-(25-a)^2
solve to get a=9, so b=16

So, r^2+9^2 = 15^2
r^2 = 225-81=144

area of semi-circle is 1/2 pi r^2 = 72pi
Answered by Knights
Thanks a lot!
Answered by AOPS
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Answered by Overseer
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Answered by AoPS
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Answered by Anonymous
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Answered by AoPS
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Answered by JEFF
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Answered by Richard Rusczyk
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Answered by aops real one 100%
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Answered by Anonymous
facts tho
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