Asked by Anonymous
a converging lens has a focal length of 15cm. Find two positions where a real object can produce images four times its size.
Answers
Answered by
drwls
Di = 4 Do, or
Di = -4 Do
will both work.
Di = image distance
Do = object distance
First case:
1/Di + 1/Do = 1/f = 1/15
1/(4Do) + 1/Do = 1/15
5/(4Do) = 1/15
Do = 75/4 = 18.75 cm
Second case:
-1/4Do + 1/Do = 1/15
3/(4Do) = 1/15
4 Do = 45
Do = 11.25 cm
Di = -4 Do
will both work.
Di = image distance
Do = object distance
First case:
1/Di + 1/Do = 1/f = 1/15
1/(4Do) + 1/Do = 1/15
5/(4Do) = 1/15
Do = 75/4 = 18.75 cm
Second case:
-1/4Do + 1/Do = 1/15
3/(4Do) = 1/15
4 Do = 45
Do = 11.25 cm
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.