Asked by cr
A thin converging lens of focal length 9.82 cm
forms an image of an object placed 18.5 cm
from the lens.
Find the image distance.
Answer in units of cm.
What is the magnification for an object distance of 18.5 cm?
Find the location of the image for an object
distance of 4.06 cm.
Answer in units of cm.
Calculate the magnification for an object distance of 4.06 cm.
forms an image of an object placed 18.5 cm
from the lens.
Find the image distance.
Answer in units of cm.
What is the magnification for an object distance of 18.5 cm?
Find the location of the image for an object
distance of 4.06 cm.
Answer in units of cm.
Calculate the magnification for an object distance of 4.06 cm.
Answers
Answered by
drwls
You missed a very important lecture. The lens law.
Do = object distance
Di = image dstance
f = focal length
1/Do + 1/Di = 1/f
magnification = |Di/Do|
Try using those formulas for these questions. You need to learn how to use them to pass your course.
Do = object distance
Di = image dstance
f = focal length
1/Do + 1/Di = 1/f
magnification = |Di/Do|
Try using those formulas for these questions. You need to learn how to use them to pass your course.
Answered by
cr
The first answer is 20.93, then when I take that and divide it by 18.5 equals 1.13 but that is incorrect. What am I doing wrong? Then using the same formula (1/9.82)- (1/4.06) comes out -6.92 which doesn't seem right either. please help.
Answered by
cr
I was able to get distance but both my magnifications were incorrect. pls help
Answered by
cr
Got it ~ thanks!
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