Asked by Crystal
Precalc
(1+i)^3
and
the cube root of 8i
(1+i)^3
and
the cube root of 8i
Answers
Answered by
Steve
(1+i) = (√2,pi/4)
so, (1+i)^3 = (2√2,3pi/4) = (-2+2i)
8i = (8,pi/2)
(8i)^(1/3) = (2,pi/6) = (√3+i)
so, (1+i)^3 = (2√2,3pi/4) = (-2+2i)
8i = (8,pi/2)
(8i)^(1/3) = (2,pi/6) = (√3+i)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.