Question
what mass of a sample of gold requires 1.75 kJ to change its temperature from 28.2 degrees Celsius to 89.5 degrees Celsius?
Answers
Devron
The equation needed is
q=mc∆T
where
q=1.75 kJ =1750 j
m=?
c=0.129 J/g ºC
∆T=89.5ºC-28.2ºC=61.3ºC
Solve for m,
q/c∆T=m
1750 j/[0.129 J/g ºC*(61.3ºC)]=m
q=mc∆T
where
q=1.75 kJ =1750 j
m=?
c=0.129 J/g ºC
∆T=89.5ºC-28.2ºC=61.3ºC
Solve for m,
q/c∆T=m
1750 j/[0.129 J/g ºC*(61.3ºC)]=m