Pls help..
Q: prepare a table of value for acid-base titration using 26.40cm^3 as end point
2 answers
I THINK YOU NEED MORE INFO THEN THAT.
I think the problem is to be made up to meet that criteria. For example, if we start with 25 mL of 0.1M HCl we start with 2.5 millimols. For the end point to be at 26.4 cc we need to use 0.0947 M NaOH.
Then zero mL NaOH, (H^+) = 0.1 M and pH = 1.
End point is 25*0.1/26.4*0.947.
So you make a table starting with zero mL HCl and and ending with the equivalence point. You can add point in between.
Then zero mL NaOH, (H^+) = 0.1 M and pH = 1.
End point is 25*0.1/26.4*0.947.
So you make a table starting with zero mL HCl and and ending with the equivalence point. You can add point in between.