Asked by Tim

If the molality of a CaCl2 solution is .100 mol/kg, and was made from 500.0 mL of water, how many grams of CaCl2 were needed to make the solution?

Step by step would be appreciated!
Answered by Tim
DrBob222, do you know how to do this?
Answered by Devron
The density of H2O=1g/mL, solve for mass.

mass=density*volume=(1g/mL)*(500mL)=500g or 0.500 kg

m=moles of solute/kg of solvent, solve for moles


(0.100 mol/kg)*(0.500 kg)= moles of CaCl2

moles of CaCl2*(111.0g/mole)= mass of CaCl2


****I'm not Dr. Bob222, but I think this is correct.
Answered by DrBob222
I'll buy all of that. Something like 5.55 g if I punched in the right numbers
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