Asked by john
for each of the following synthesis reaction indentify the missing reactant(s) or product(s) and then balance the resulting equation
a) Mg +__________ ----------> MgO
b) _________ + O2-----------> Fe2O3
c) Li + Cl2 -------> _________
d) Ca + __________------> CaI2
a) Mg +__________ ----------> MgO
b) _________ + O2-----------> Fe2O3
c) Li + Cl2 -------> _________
d) Ca + __________------> CaI2
Answers
Answered by
DBob222
Tell me what you don't understand about these problems. It appears obvious to me that the first one must have O2 added to it to obtain MgO.
Mg + O2 ==> MgO, then balance by
2Mg + O2 ==> 2MgO
The others are done the same way.
Mg + O2 ==> MgO, then balance by
2Mg + O2 ==> 2MgO
The others are done the same way.
Answered by
john
so for B) would it be 2Fe2O3?
c) 1LiCl2
d) 2Cal2
c) 1LiCl2
d) 2Cal2
Answered by
DrBob222
B is Fe + O2 ==> Fe2O3. then balance to give
4Fe + 3O2 ==> 2Fe2O3
C is Li + Cl2==> LiCl (the valence of Li is 1 and Cl is 1; therefore, the formula is LiCl. Then balance.
d. Ca + I2 ==> CaI2, then balance.
4Fe + 3O2 ==> 2Fe2O3
C is Li + Cl2==> LiCl (the valence of Li is 1 and Cl is 1; therefore, the formula is LiCl. Then balance.
d. Ca + I2 ==> CaI2, then balance.
Answered by
john
so C is 1Li1Cl
d is Ca2l2?
d is Ca2l2?
Answered by
DrBob222
C is
Li + Cl2 ==> LiCl, then if you want to balance it it is
2Li + Cl2 ==> 2LiCl (Placing a 1, as in Li1Cl, is not wrong BUT no one does it BECAUSE if we write Li we imply there is one of Li; therefore, we don't write the 1s, only numbers that are not 1. )
I don't know where you get Ca2I2?
Ca + I2 ==> CaI2 and it is balanced as is.
Li + Cl2 ==> LiCl, then if you want to balance it it is
2Li + Cl2 ==> 2LiCl (Placing a 1, as in Li1Cl, is not wrong BUT no one does it BECAUSE if we write Li we imply there is one of Li; therefore, we don't write the 1s, only numbers that are not 1. )
I don't know where you get Ca2I2?
Ca + I2 ==> CaI2 and it is balanced as is.
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