Asked by Chris
The forensic technician at a crime scene has just prepared a luminol stock solution by adding 15.0g of luminol into a total volume of 75.0 \rm mL of \rm H_2O.
What is the molarity of the stock solution of luminol? 1.13M
Before investigating the scene, the technician must dilute the luminol solution to a concentration of 6.00×10−2\it M . The diluted solution is then placed in a spray bottle for application on the desired surfaces.
How many moles of luminol are present in 2.00 L of the diluted spray? 0.120 moles
What volume of the stock solution (Part A) would contain the number of moles present in the diluted solution (Part B)?
Answers
Answered by
DrBob222
mols = grams/molasr mass = about 0.08 mols, then 0.08/0.075 = about 1.13. You need to do this more accurately.
mols = M x L = 0.06 x 2L = ?
M = mols/L. You know mols and M, solve for L and convert to mL.
mols = M x L = 0.06 x 2L = ?
M = mols/L. You know mols and M, solve for L and convert to mL.
Answered by
Chris
is there a formula that i am suppose to use?
Answered by
DrBob222
I gave you the formulas.
First determine moles which = grams/molar mass.
Then molarity = M = mols/L soln.
The last part is
M = mols/L.
First determine moles which = grams/molar mass.
Then molarity = M = mols/L soln.
The last part is
M = mols/L.
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