Next step, multiply both sides by (.01-x)

.012(.01-x)=.01x+x^2

gather terms, put in standard binomial form, use the quadratic equation, and solve for x.

is the standard binomial x^2+.022x-1.2x10^-4

2 answers

yes. That is the correct quadratic equation. Now solve for x. Then (H^+) = 0.01 + x and pH = -log(H^+).
yes.
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