Asked by Kyle
Use intermediate value theorem to show there is a root to 2x^3 + x^2 - 2 = 0 on [0,1]
Answers
Answered by
Reiny
f(0) = -2
f(1) = 2+1-2 = 1
mmmhhh, how did the graph get from -2 to +1 ?
f(1) = 2+1-2 = 1
mmmhhh, how did the graph get from -2 to +1 ?
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