Asked by anoynomous
The diameter of a road roller is 140cm and its length is 2.2m. It takes 400 complete revolutions to move over to level a stretch of a road 2.2m wide find the surface area of stretch of road leveled in m sq.
Answers
Answered by
Steve
area = (400)(pi)(1.4m)(2.2m) = 3870 m^2
Answered by
anoynomous
diameter is 140cm
it 's not radius sir
it 's not radius sir
Answered by
Steve
that's why I showed the circumference as pi*d, and not 2pi * r
Still, thanks for checking my work.
Still, thanks for checking my work.
Answered by
Chirag Gupta
I dont know how can we solve this question please help me and give me the answer of this question
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