Asked by Anonymous
The diameter of a roller is 80 cm and its length is 126 cm. It takes 750 complete revolution once over to level a playground. find the area of the ground.
Answers
Answered by
Steve
the roller's curved surface area is
2pi r h = 2pi * 40 * 126 = 31667 cm^2
750 revolutions will thus cover 23750420 cm^2 = 2375 m^2
2pi r h = 2pi * 40 * 126 = 31667 cm^2
750 revolutions will thus cover 23750420 cm^2 = 2375 m^2
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