Asked by beth49
Find the general solution to the differential equation:
yy’ – x2 = 3.
yy’ – x2 = 3.
Answers
Answered by
Steve
yy' - x^2 = 3
1/2 (2y y') = (x^2+3)
(y^2)' = 2 (x^2+3)
y^2 = 2/3 x^3 + 3x + C
= 2/3 (x(x^2+9)+C)
y = ±√(2/3) √(x(x^2+9)+C)
1/2 (2y y') = (x^2+3)
(y^2)' = 2 (x^2+3)
y^2 = 2/3 x^3 + 3x + C
= 2/3 (x(x^2+9)+C)
y = ±√(2/3) √(x(x^2+9)+C)
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