Asked by rebekah
Find the general solution of the equation.
6t*dy/dt+y=sqrt (t),t>0.
6t*dy/dt+y=sqrt (t),t>0.
Answers
Answered by
Steve
6t dy/dt + y = √t
y' + 1/6t y = 1/(6√t)
You want an integrating factor:
e^(∫1/(6t) dt) = t^(1/6)
Now the equation becomes
t^(1/6) y' + 1/6 t^(-5/6) y = 1/(6∛t)
d(t^(1/6) y) = 1/(6∛t)
t^(1/6) y = 1/4 t^(2/3) + c
y = 1/4 √t + c/t^(1/6)
y' + 1/6t y = 1/(6√t)
You want an integrating factor:
e^(∫1/(6t) dt) = t^(1/6)
Now the equation becomes
t^(1/6) y' + 1/6 t^(-5/6) y = 1/(6∛t)
d(t^(1/6) y) = 1/(6∛t)
t^(1/6) y = 1/4 t^(2/3) + c
y = 1/4 √t + c/t^(1/6)
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