Asked by ryan j
help find the general solution of the following first order differential equation.
t*(dy/dt) = (-y/t) + ((exp(1/t)/t^3)
could you show steps in working to sol.
t*(dy/dt) = (-y/t) + ((exp(1/t)/t^3)
could you show steps in working to sol.
Answers
Answered by
Steve
I like x instead of t. You have
xy' = -y/x + e^(1/x) / x^3
Change to the form
y' + yP(x) = Q(x)
y' + y*1/x<sup>2</sup> = e<sup>1/x</sup>/x<sup>4</sup>
Now find the integrating factor
IF = exp(Int(P(x)) = exp(Int(1/x<sup>2</sup>)) = e<sup>-1/x</sup>
Now, y = 1/e<sup>-1/x</sup> Int(Q(x)*IF)
= e<sup>1/x</sup> Int(e<sup>1/x</sup>/x<sup>4</sup> * e<sup>-1/x</sup> dx)
= e<sup>1/x</sup>*(-1/3x<sup>3</sup> + C)
y = Ce<sup>1/x</sup> - e<sup>1/x</sup>/3x<sup>3</sup>
xy' = -y/x + e^(1/x) / x^3
Change to the form
y' + yP(x) = Q(x)
y' + y*1/x<sup>2</sup> = e<sup>1/x</sup>/x<sup>4</sup>
Now find the integrating factor
IF = exp(Int(P(x)) = exp(Int(1/x<sup>2</sup>)) = e<sup>-1/x</sup>
Now, y = 1/e<sup>-1/x</sup> Int(Q(x)*IF)
= e<sup>1/x</sup> Int(e<sup>1/x</sup>/x<sup>4</sup> * e<sup>-1/x</sup> dx)
= e<sup>1/x</sup>*(-1/3x<sup>3</sup> + C)
y = Ce<sup>1/x</sup> - e<sup>1/x</sup>/3x<sup>3</sup>
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.