Asked by Anonymous
Write the trigonometric expression as an algebraic expression.
sin(arcsinx+arccosx)
sin(arcsinx+arccosx)
Answers
Answered by
Steve
sin arcsinx cos arccosx + cos arcsinx sin arccosx
= x*x + √(1-x^2) √(1-x^2)
= x^2 + 1-x^2
= 1
Naturally, since arcsinx + arccosx = pi/2
= x*x + √(1-x^2) √(1-x^2)
= x^2 + 1-x^2
= 1
Naturally, since arcsinx + arccosx = pi/2
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