the volume of a monoatomic ideal gas doubles in an adiabatic expansion. by considering 135 moles of gas with an initial pressure of 330kPa and an initial volume of 1.2m^3, the gas is then expands adiabatically to a volume of 2.4m^3.

Question

FIND THE WORK DONE BY THE GAS.

Thank you.

Answer 1

γ=(i+2)/i=5/3=1.67

W=νRT₁ /(γ-1)}•{1-(V₁/V₂)^(γ-1)} =
={p₁V₁/(γ-1)}•{1-(V₁/V₂)^(γ-1)} =
=(330000•1.2/0.67) •(1-0.5^0.67)=
=591044.8•0.37 =2.2•10⁵ J