Asked by Tulika
A monoatomic gas expands isobarically.What will be the percentage of heat supplied that increases the thermal energy and that involved in doing work for expansion?
Answers
Answered by
Elena
The first law of thermodynamics
ΔQ =ΔU + W.
The work done by system is
W = p•ΔV =ν•R•ΔT.
The change in internal energy is
ΔU = ν•(i/2) •R•ΔT,
where the degrees of freedom i = 3,
ΔQ =ΔU + W = ν•(i/2) •R•ΔT + ν•R•ΔT = =2.5 •ν•R•ΔT,
ΔU/ ΔQ = ν•(i/2) •R•ΔT /2.5 •ν•R•ΔT =3/5 = 0.6.
60%
W/ ΔQ = ν•R•ΔT/2.5 •ν•R•ΔT = 0.4
40%
ΔQ =ΔU + W.
The work done by system is
W = p•ΔV =ν•R•ΔT.
The change in internal energy is
ΔU = ν•(i/2) •R•ΔT,
where the degrees of freedom i = 3,
ΔQ =ΔU + W = ν•(i/2) •R•ΔT + ν•R•ΔT = =2.5 •ν•R•ΔT,
ΔU/ ΔQ = ν•(i/2) •R•ΔT /2.5 •ν•R•ΔT =3/5 = 0.6.
60%
W/ ΔQ = ν•R•ΔT/2.5 •ν•R•ΔT = 0.4
40%