Asked by Sally
Consider only the discriminant, b2 - 4ac, to determine whether one real-number solution, two different real-number solutions, or two different imaginary-number solutions. 2x2 = -2 -5
Thank you
Thank you
Answers
Answered by
Dr. Jane
Are you missing an x?
2x^2 + 2x + 5 = 0
a = 2
b=2
c = 5
If your answer = 0 then there is only 1 real number solution.
If your answer = any positive number you will have two real solutions
If your answer = any negative number you will have two imaginary solutions.
All of the above happens because in the quadratic equation you take +/- the square root of b^2-4ac
2x^2 + 2x + 5 = 0
a = 2
b=2
c = 5
If your answer = 0 then there is only 1 real number solution.
If your answer = any positive number you will have two real solutions
If your answer = any negative number you will have two imaginary solutions.
All of the above happens because in the quadratic equation you take +/- the square root of b^2-4ac
Answered by
Daphne
What is the commutative law of addition to find an expressoon equivalent to 5m + 9n
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