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if the discriminant of (5u^2)+bu+2=0 is 41, what are all the values of b

2 answers

The discriminant of a quadratic equation
Ax²+Bx+C=0
is
Δ=B&sup2-4AC
Here A=5,B=b,C=2
so
Δ=b²-4*5*2=41
Solve for b to get b=sqrt(1)

what is the final answer?

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