Asked by rick5555
Calculate the indefinite integral:
∫(4x-3/x)dx
∫(4x-3/x)dx
Answers
Answered by
bobpursley
INT 4 dx - 3INTdx/x
4x-3lnx + Constant
Or you could have meant this (check parenthesis )
INT( 4x dx-3dx/x)=2x^3 -3lnx + C
4x-3lnx + Constant
Or you could have meant this (check parenthesis )
INT( 4x dx-3dx/x)=2x^3 -3lnx + C
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