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Asked by rick5555

Calculate the indefinite integral:

∫(4x-3/x)dx
12 years ago

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Answered by bobpursley
INT 4 dx - 3INTdx/x

4x-3lnx + Constant

Or you could have meant this (check parenthesis )

INT( 4x dx-3dx/x)=2x^3 -3lnx + C
12 years ago
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Calculate the indefinite integral:

∫(4x-3/x)dx

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