Question

S(12x+6)(3x^2+3x+5)^7
S=integral sign
please help I am stuck :(
Steve
(12x+6)(3x^2+3x+5)^7 dx
= 2(3x^2+3x+5)^7 (6x+3) dx
Let
u = 3x^2+3x+5
du = 6x+3 dx

so, now your integrand is just

2u^7 du

not so hard now, eh?