Asked by Katlynn
Use inverse trigonometric functions to find the solutions of the equation that are in the given interval, and approximate the solutions to four decimal places. (Enter your answers as a comma-separated list.)
10 sin^2 x = 3 sin x + 4; [0, 2π)
10 sin^2 x = 3 sin x + 4; [0, 2π)
Answers
Answered by
Reiny
10 sin^2 x - 3sinx - 4 = 0
(2sinx + 1)(5sinx - 4) = 0
sinx = -1/2 or sinx = 4/5
if sinx = -1/2, (x must be in III or IV)
x = 210° or 330°
if sinx = 4/5 , (x must be in I or II)
x = 53.1301 or x = 126.8699°
(2sinx + 1)(5sinx - 4) = 0
sinx = -1/2 or sinx = 4/5
if sinx = -1/2, (x must be in III or IV)
x = 210° or 330°
if sinx = 4/5 , (x must be in I or II)
x = 53.1301 or x = 126.8699°
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