Asked by Soyer
Which basic trigonometric function has the same graph as y= -cot(x+(pi/2)).Please justify your answer.
Answers
Answered by
drwls
y = -cot(x+(pi/2))
= -cos(x + pi/2)/sin (x + pi/2)
= (-cosx*cospi/2)-sinx*sin pi/2)/
[(sinx cos pi/2)-cosx*sin pi2)]
= -sinx/-cosx = tanx
= -cos(x + pi/2)/sin (x + pi/2)
= (-cosx*cospi/2)-sinx*sin pi/2)/
[(sinx cos pi/2)-cosx*sin pi2)]
= -sinx/-cosx = tanx
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