Asked by natash
when an aqueous solution suspected of containing BA2+ or Pb2+ or both is mixed with sulfuric acid a precipitate forms. In another test, when the original solution is mixed with an aqueous solution of sodium sulfide no precipitate forms. What do these two tests indicate about the likely presence of Ba2+ and Pb2+ in the original solution? Explain your answer.
Answers
Answered by
DrBob222
Pb is present. Ba is not present. Do you know why?
Ba^+2 + SO4^= ==> BaSO4(s) white ppt.
Pb^+2 + SO4^= ==> PbSO4(s) white ppt.
Ba^+2 + S^= ==> BaS is soluble; therefore, no ppt.
Pb^+2 + S^= ==> PbS(s) black ppt.
Ba^+2 + SO4^= ==> BaSO4(s) white ppt.
Pb^+2 + SO4^= ==> PbSO4(s) white ppt.
Ba^+2 + S^= ==> BaS is soluble; therefore, no ppt.
Pb^+2 + S^= ==> PbS(s) black ppt.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.