Asked by Anonymous

If an 0.650 m aqueous solution freezes at –2.00 °C, what is the van't Hoff factor, i, of the solute? Kf values can be found here.

the Kf value is 1.86 °C/m.

I get 2 for the answer but it is wrong. Please help!

Answers

Answered by DrBob222
delta T = i*Kf*m
2.00 = i*1.86*0.650
i = (2.00/1.86*0.65) = ?
I obtained 1.65 for i.
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