Asked by Katie
6^(2log(x)) = 8
Answers
Answered by
Steve
assuming logs base 10,
2logx = log_6(8)
logx = 1/2 log_6(8)
x = √(10^(log_6(8))
now log_6(8) = log6/log8. so
x = √(10^log6)^(1/log8)
= √(6^1/log8)
= 6^(1/log64)
2logx = log_6(8)
logx = 1/2 log_6(8)
x = √(10^(log_6(8))
now log_6(8) = log6/log8. so
x = √(10^log6)^(1/log8)
= √(6^1/log8)
= 6^(1/log64)
Answered by
Reiny
take log of both sides
log [ 6^(2logx) ] = log8
2logx (log6) = log8
2logx = log8/log6
log x^2= log8/log6
x^2= 10^(log8/log6)
x = √( 10^(log8/log6) ) = 3.804339012
check using your calculator, it works
log [ 6^(2logx) ] = log8
2logx (log6) = log8
2logx = log8/log6
log x^2= log8/log6
x^2= 10^(log8/log6)
x = √( 10^(log8/log6) ) = 3.804339012
check using your calculator, it works
Answered by
Steve
Go with Reiny's answer. I messed up my log base conversion.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.