Asked by ellis
the areas of two rectangles are 15 square inches and 16 square inches. the length and width of both figures are whole numbers. if the rectangles have the same width, what is the greatest possible value for their widths? please show work
Answers
Answered by
ellis
please
Answered by
Reiny
area of first = length1 x width
15 = length1 x width
width = 15/length1
area of 2nd:
16 = length2 x width
width = 16/length2
so length2/length1 = 16/15
the length of the first is 15, its width is 1
the length of the 2nd is 16, its width is 1
the largest value of the width has to be 1
15 = length1 x width
width = 15/length1
area of 2nd:
16 = length2 x width
width = 16/length2
so length2/length1 = 16/15
the length of the first is 15, its width is 1
the length of the 2nd is 16, its width is 1
the largest value of the width has to be 1
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