Asked by tony

how many rectangles can have the perimiter of 46m
Answered by Anonymous
P = 2 W + 2 L

P = 2 ( W + L )


46 = 2 ( W + L ) Divide both sides by 2

46 / 2 ) = 2 ( W + L ) / 2

23 = W + L

W + L = 23


For integers :

W = 1 m

L = 22 m


W = 2 m

L = 21 m

W = 3 m

L = 20 m

etc.
Answered by math
math
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