Asked by ashley
the primeter of a rectangle is 24ft. the length is 2 ft longer than the width. Find the dimensions. Write a system of linear equations and solve the resulting system. Let x be the length and y be the width.
Is the answer for the lenght 16ft
and 8ft for the width?
Is the answer for the lenght 16ft
and 8ft for the width?
Answers
Answered by
Ms. Sue
No. Remember there are four sides to a rectangle. Also 16 is not 2 feet longer than the width.
Please try again.
Please try again.
Answered by
ashley
okay 14ft for length and 10 for the width.
Answered by
Ms. Sue
14 - 10 = 4
Your perimeter is 48 feet long.
P = 2L + 2W
24 = 2(W + 2) + 2W
Your perimeter is 48 feet long.
P = 2L + 2W
24 = 2(W + 2) + 2W
Answered by
ashley
I am getting lost here. I came up with 8 ft for the length and 4 ft for the width. I hope this is right.
Answered by
Ms. Sue
But the length is only 2 feet longer than the width.
24 = 2(W + 2) + 2W
24 = 4W + 4
20 = 4W
5 = W
~~~~~~~~~~~~~~~~~~~~~
5 + 2 = 7
Length = 7
Let's see if that produces a perimeter of 24
5 + 5 + 7 + 7 = 24
24 = 2(W + 2) + 2W
24 = 4W + 4
20 = 4W
5 = W
~~~~~~~~~~~~~~~~~~~~~
5 + 2 = 7
Length = 7
Let's see if that produces a perimeter of 24
5 + 5 + 7 + 7 = 24
Answered by
ashley
thanks so much.
Answered by
Ms. Sue
You're very welcome.
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