Question
Is it possible for a rectangle with a perimeter of 44cm to have the area of 125cm^2 ? If so, find the dimensions of the rectangle.
Figure out the equation in general form.
Figure out the equation in general form.
Answers
It is not possible.
The largest area is when the perimeter of 44 describes a square, namely of 11" per side, which gives an area of 11²=121 < 125.
I assume you are in grade 11, so cannot use calculus to explain. But generally, the rectangle with the largest area for the same perimeter is a square.
If it were possible, then we have the equations:
b*h=A
2(b+h)=P
where b,h represent the dimensions of the rectangle, and A and P represent area and perimeters.
You can then solve for b and h given A and P.
The largest area is when the perimeter of 44 describes a square, namely of 11" per side, which gives an area of 11²=121 < 125.
I assume you are in grade 11, so cannot use calculus to explain. But generally, the rectangle with the largest area for the same perimeter is a square.
If it were possible, then we have the equations:
b*h=A
2(b+h)=P
where b,h represent the dimensions of the rectangle, and A and P represent area and perimeters.
You can then solve for b and h given A and P.
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