Asked by anchal
The hypotenuse of a right angled triangle is 20 m. If the difference between the length of the other sides be 4m. find the other sides?
Answers
Answered by
Dr. Jane
This is a right triangle problem with
c^2 = a^2 + b^2
The difference between a and b is 4.
a- b = 4 or a = b +4
20^2 = (b+4)^2 + b^2
To find the answer you have to multiply (b+4)(b+4) and add b^2.
Next subtract the 400 from both sides so that you have 0 = on one side.
Factor and solve for b. Then you can find a.
c^2 = a^2 + b^2
The difference between a and b is 4.
a- b = 4 or a = b +4
20^2 = (b+4)^2 + b^2
To find the answer you have to multiply (b+4)(b+4) and add b^2.
Next subtract the 400 from both sides so that you have 0 = on one side.
Factor and solve for b. Then you can find a.
Answered by
anon
The sides of a hypotenuse are all multiples of the original Pythagorean triple: 3, 4, 5. Obviously in this, 5 is the hypotenuse and in your equation so is 20. To get 20, you have to multiply 5 by four so to get the Pythagorean triple you just need to multiply the original set by 4. So your answer will be 12, 16 and 20.
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