Asked by Bankai
The hypotenuse of a right angled triangle is 65cm. One side is 10 cm shorter than twice the other side. Find the lengths of the 2 sides
(provide a little of steps if available)
(provide a little of steps if available)
Answers
Answered by
drwls
The Pythagorean theorem tells you that
65^2 = x^2 + (2x -10)^2
4225 = 5x^2 -40x + 100
Now collect terms
5x^2 -40x -4125 = 0
Divide by 5 to simplify.
x^2 -8x - 825 = 0
That equation can be factored.
(x+25)(x-33) = 0
The only positive root is x = 33 cm
The other side must be 56 cm long
65^2 = x^2 + (2x -10)^2
4225 = 5x^2 -40x + 100
Now collect terms
5x^2 -40x -4125 = 0
Divide by 5 to simplify.
x^2 -8x - 825 = 0
That equation can be factored.
(x+25)(x-33) = 0
The only positive root is x = 33 cm
The other side must be 56 cm long
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