Asked by zachary
given the following polynomial find the zero and multiply of each
were the graph touches the x axis
number of turning points
fx =(x-4)(x^2-25)
were the graph touches the x axis
number of turning points
fx =(x-4)(x^2-25)
Answers
Answered by
Dr. Jane
0 = (x-4)(x+5)(x-5)
Set each equal to zero and solve for x. That will give you three different zeros. Each occurs only once.
Set each equal to zero and solve for x. That will give you three different zeros. Each occurs only once.
Answered by
Steve
f(x) = (x-4)(x-5)(x+5)
3 roots, each of multiplicity 1
The graph crosses the axis at each root, so it has to turn around 2 times.
3 roots, each of multiplicity 1
The graph crosses the axis at each root, so it has to turn around 2 times.
Answered by
Anonymous
4
-5
5
-5
5
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