0 = (x-4)(x+5)(x-5)
Set each equal to zero and solve for x. That will give you three different zeros. Each occurs only once.
given the following polynomial find the zero and multiply of each
were the graph touches the x axis
number of turning points
fx =(x-4)(x^2-25)
3 answers
f(x) = (x-4)(x-5)(x+5)
3 roots, each of multiplicity 1
The graph crosses the axis at each root, so it has to turn around 2 times.
3 roots, each of multiplicity 1
The graph crosses the axis at each root, so it has to turn around 2 times.
4
-5
5
-5
5