Question
polynomial
with h+vt-4.9^2
50 meters high
30 meters per sec.
what is height after 2 sec.
with h+vt-4.9^2
50 meters high
30 meters per sec.
what is height after 2 sec.
Answers
Marth
Plug the values in.
h = 50m
t = 2s
v = 30m/s
h+vt+4.9*t^2=?
h = 50m
t = 2s
v = 30m/s
h+vt+4.9*t^2=?
Damon
h+vt-4.9 t^2 (typo)
from
h = Ho + Vo t + (1/2) a t^2
where a = gravity = 9.8 m/s^2
Ho, initial height = 50m
Vo = initial velocity up = 30
so
50 + 30 (2) - 4.9 (4)
= 110 - about 20 = about 90
you use your calculator
from
h = Ho + Vo t + (1/2) a t^2
where a = gravity = 9.8 m/s^2
Ho, initial height = 50m
Vo = initial velocity up = 30
so
50 + 30 (2) - 4.9 (4)
= 110 - about 20 = about 90
you use your calculator
Damon
typo a = -9.8m/s^2
(down)
(down)