Asked by Chris
A specimen has .625 the amount of carbon 14 you would find in a living specimen.
How many half-lives has the specimen been through?
How old is the specimen?
How many half-lives has the specimen been through?
How old is the specimen?
Answers
Answered by
Damon
.5^n = .625
n ln .5 = ln .625
n = -.470/-.693 = 0.678 half lives
.678*5730 = 3885 years
n ln .5 = ln .625
n = -.470/-.693 = 0.678 half lives
.678*5730 = 3885 years
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