Asked by Leanna

A 23 kg child goes down a straight slide inclined 38 degrees above horizontal. The child is acted on by his weight, the normal force from the slide, and kinetic friction.
Answered by Leanna
(23kg)(9.8m/s^2)(cos(38)) = 177.6N
Answered by Damon
You do not say if the child is going at constant speed or alternatively what the coef of friction is. You also do not say what the question is.
Answered by Damon
All I can say is
normal force = 23 * 9.81 * cos 38 = 178 N agreed

force down slide = 23 * 9.81 * sin 38 = 139 N

force up slide = 178 * mu
so

23 a = 139 - 178 mu

if a = zero, you can solve for mu
if you know mu, you can solve for a
Answered by Pablo
The normal force is 160 N. I am not quite sure how to find it though. The back of my textbook just says 160 N.
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