Question

Two points C and P lie on straight line such that C is due north of P.Another point T is 6km away from the line CP on a bearing of 150 degree from C and 40 degree from P.what is the length of the line CP?
Steve
Draw a diagram. It is clear that angle T is 120 degrees. So, using the law of sines,

CP/sin120 = 6/sin40
Anonymous
Pls can u show the diagram