Asked by Abhishek
what is the power dissipated in an ac circit in which current v=230sin(wt+90) and I=10sin(wt)...plz help me
Answers
Answered by
bunnybhargav
Pav=(VoIo x cos @)/2
Pav=(230x10)/2 since cos@ is 1 power factor.
Pav=1150 w.
Pav=(230x10)/2 since cos@ is 1 power factor.
Pav=1150 w.
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