Asked by harold
what is the power dissipated by a 10 ohm resistor through which a 2 ampere current is flowing?
Answers
Answered by
Luckyme
V = I x R
P = V x I
P = R x I^2
P = 10 x 2^2 = 40 watts = 136.5 btu/hr
P = V x I
P = R x I^2
P = 10 x 2^2 = 40 watts = 136.5 btu/hr
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