Question
how many grams of oxygen gas will be required to react completely with 92.0 grams of solid sodium to form solid sodium oxide?
Answers
4Na + O2 → 2Na2O
92.0g of Na*(1 mole/22.98g of Na)*(2 moles of Na2O /4 moles of Na)*(61.98 g of Na2O/1 mol)= mass of Na2O
92.0g of Na*(1 mole/22.98g of Na)*(2 moles of Na2O /4 moles of Na)*(61.98 g of Na2O/1 mol)= mass of Na2O
32.0 g 02
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