Speed acquired at end of ramp
Ve = sqrt(2 g H) = 18.73 m/s
That can be derived using conservation of energy.
The upward vertical component of velocity at the edge of the ski jump is
Vy = Ve*sin28 = 8.79 m/s
That is enough to cause a vertical rise (above the end of the jump) equal to
y = Vy^2/(2*g) = 3.94 m
A 44 kg skier starts from rest at a height of H = 18 m above the end of the ski-jump ramp. As the skier leaves the ramp, his velocity makes an angle of 28° with the horizontal. Neglect the effects of air resistance and assume the ramp is frictionless.
(a) What is the maximum height h of his jump above the end of the ramp?
m
1 answer
1 answer