Asked by ursula

Two professional downhill skiers are racing at the speeds shown in the diagram. *Skier 1 is going 100 ft/s, and Skier 2 is going 110 ft/s. Skier 1 starts 5 seconds before Skier 2. The course is 5000 ft long. Will Skier 2 pass Skier 1?
Answered by oobleck
5000/100 = 50
5000/110 = 45.45
so, since skier 1 started 5 seconds early, he will finish 0.55 seconds ahead
Answered by ursula
Thank you!
Answered by ursula
Can I ask why you divided the course length by the speeds?
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