Asked by Cindy
An automobile with 0.80-m diameter wheel starts from rest and accelerates uniformly to 22 m/s in 0.7 s. Through how many revolutions does the front wheel turn during this period?
Answers
Answered by
Damon
r = .4 m
v = w r = 22
so w final = 22/.4 = 55 radians/second
alpha = 55/.7 = 78.6 radians/s^2
angle = (1/2) a t^2
= .5(78.6)(.49) = 19.25 radians
19.25/(2 pi) = 3.05 revolutions
v = w r = 22
so w final = 22/.4 = 55 radians/second
alpha = 55/.7 = 78.6 radians/s^2
angle = (1/2) a t^2
= .5(78.6)(.49) = 19.25 radians
19.25/(2 pi) = 3.05 revolutions
There are no AI answers yet. The ability to request AI answers is coming soon!