Question

1) A 1 kg mass moving at 1 m/s has a totally inelastic collision with a 0.7 kg mass. What is the speed of the resulting combined mass after the collision?

2) A cart of mass 1 kg moving at a speed of 0.5 m/s collides elastically with a cart of mass kg at rest. The speed of the second mass after the collision is 0.667 m/s. What is the speed 1 kg mass after the collision?

3) A 0.010 kg bullet is shot from a 0.500 kg gun at a speed of 230 m/s. Find the speed of the gun.

4)Two carts with a masses of 4 kg and 3 kg move toward each other on a frictionless track with speeds of 5.0 m/s and 4 kg m/s respectively. The carts stick together after the colliding head on. Find the final speed.

5) A cart of mass 1.5 kg moving at a speed of 1.2 m/s collides elastically with a cart of mass 1.0 kg moving at a speed of 0.75 m/s. (the carts are moving at the same direction)The speed
of the second mass (1.0 kg) after the collision is 0.85 m/s. What is the speed
of the 1.5 kg mass after the collision?

please help me!

>>FORMULA's<<
W=Fd
F=ma
W=mad
J=Ft or J=p
Ft=mvf-mvi
P=w/t
P=energy/time
P=mad/t
P= Fd/t

>> I'm so sorry, please help me! :) and Thank You!!

Answer 1

5. M1 = 1.5kg, V1 = 1.2 m/s.
M2 = 1.0kg, V2 = 0.75 m/s.
V3 = Velocity of M1 after the collision.
V4 = 0.85 m/s. = Velocity of M2 after the collision.

Conservation of KE Eq.
V3 = (V1(M1-M2) + 2M2*V2)/(M1+M2).
V3=(1.2(1.5-1.0)+2*0.75)/(1.5+1.0) = 0.84 m/s. = Velocity of M1 after the collision.

Answer 2

Correction:
5. M1*V1 + M2*V2 = M1*V3 + M2*V4.
1.5*1.2 + 1.0*0.75 = 1.5*V3 + 1.0*V4,
1.5*V3 + 1.0*V4 = 2.55,
Replace V4 with 0.85 and solve for V3:
1.5*V3 + 0.85 = 2.55,
1.5V3 = 2.55-0.85 = 1.7,
V3 = 1.13 m/s. = Velocity of M1 after the collision.