Asked by Mrsi

A car of mass 600 kg is moving at a speed of 20 m/s.it collides with a stationary car of mass 900 kg.if the first car bounces back at 4 m/s,at what speed does the second car move after the collusion?
Answered by oobleck
conserve momentum.
600*20 + 900*0 = 600(-4) + 900v
Answered by Rahma abdi rahmaan
Jigjiga




1995
Answered by feruza
v=600*20-600*(-4)/900
=16
Answered by Taddy
50.6
Answered by nebiyu
(600kg*20m/s)+(900kg*0m/s)=[600kg*(-4m/s)]+900kg V2
12,000kgm/s + 0 = -2400kgm/s + (900kg)V2
12,000kgm/s + 2400kgm/s = 900kg V2
14,400kgm/s = 900kg V2
v2 = 14,400kgm/s / 900kg
v2 = 144m/s / 9
v2 = 16m/s
Answered by Lost is correct
sup dupie
Answered by Selina Gashahun
I LIKE PHYSICS
Answered by Nati
Nati man
Answered by Natnael
Given
M1=600kg
U1=20m/s
M2=900kg
U=0
Req
V2=?
Solution
M1u1+M2u2=v(m1+m2)
600kg*20m/sec+900kg*0=(600kg*-4m/s)+900kgv2=
12000kgm/s=-2400kgm/s+900kgv2
12000kgm/s+2400kgm/s=900kgv2
14400kgm/s=900kgv2
v2=16m/s
Answered by stops
aiconaa
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