Asked by Kelly
F(x) = 2√(1 + tanx)
f'(x)
2√ = x^(1/2)
f'(x)
2√ = x^(1/2)
Answers
Answered by
Steve
√ is square root. the 2 just confuses things
F = √(1+tanx) = √u
F' = 1/(2√u) u' = sec^2(x)/(2√(1+tanx))
F = √(1+tanx) = √u
F' = 1/(2√u) u' = sec^2(x)/(2√(1+tanx))
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